.0001x^2+20x-21000=0

Solution for .0001x^2+20x-21000=0 equation:

.0001x^2+20x-21000=0

a = .0001; b = 20; c = -21000;
Δ = b2-4ac
Δ = 202-4·.0001·(-21000)
Δ = 408.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-\sqrt{408.4}}{2*.0001}=\frac{-20-\sqrt{408.4}}{0.0002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+\sqrt{408.4}}{2*.0001}=\frac{-20+\sqrt{408.4}}{0.0002}
$